2022 NECO MATHEMATICS ANSWERS - Verified 2022 NECO EXAM Mathematics Questions and Answers

Obj corrected use this pls

MATHS OBJ

1-10: CBBCDCCBDC

11-20: BCABDDCADB

21-30: BBDCEBADBA

31-40: CCBABCEDDC

41-50: CCCAEDEDCE

51-60: BECDCCDDAD

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Mathematics-THEORY


All are 101% Authentic.
Pls 2bi and 4b and 9 and 12 also corrected. We Make Sure Everything
Is 101% Correct. Sorry For The Little
Corrections. Tell Others Pls.

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Type solution :

(1a)

Log¹⁰6+ Log¹⁰45 - Log¹⁰27

Log¹⁰(6*45/27) = Log(270/27)

= Log¹⁰10 = 1


(1b)

8^x = 32

2^3x = 2⁵

:. 3x = 5

x=5/3


(1c) 81⅙/27-⅑ = 3⁴*⅙/3³*-⅑ = 3⅔/3-⅓

:. 3⅔-(-⅓) = 3⅔+⅓ = 3³/³

= 3¹

= 3

====================================


(2a)

(i) Gradient (m) = y¹ - y²/x¹- x²

m = -1-0/2-3 = +1/+1=1


(ii) y - y¹= m(x-x¹)

y-0 = 1(x-3)

y = x-3

y-x+3=0


(2b)

(i) Area of ∆ABC = ½absinϴ

= ½*6*8*sin60

= 3*8*sin60

= 20.7846

= 20.78(approx)


(ii) Area of parallelogram = absinϴ

= 6*8*sin60

= 48*sin60

= 48*0.8660

= 41.6

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(3a)

|PQ| = 12km, |QP| = 12km

Speed from P to Q = 6km/h

Speed from Q to P = (6+x)km/h

Total time taken 3hrs20mins


Speed = distance/time


From P to Q = 6/1*12/t

6t = 12

t = 12/6 = 2hrs

:. Time left = 3hrs 20mins - 2hrs

= 1hr 20mins


From Q to P , Speed = distance/time


6+x = 12/ 1²⁰/⁶⁰

6+x = 12/⁴/³

6+x = 12*3/4

6+x = 9

x = 9-6 = 3


(3b)

x² - (sum)x + product = 0


Sum = ⅔ + ¾= 8+9/12 = 17/12


Products = ⅔*¾ = ½


x² - 17x/12 + ½ = 0

12x² - 17x + 6 = 0

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(4a)

Y = x²/ 1+x²

U=x² , V= 1+x²

du/dx = 2x , dv/dx = 2x


dy/dx = (vdu/dx - udv/dx)/v²

= (1+x²)2x - x² * 2x/(1+x²)²

= 2x+2x³-2x³/(1+x²)²


dy/dx = 2x/(1+x²)²


(4b)

⅔(3x +2) = ¾(2x -3


6x +4/3 = 6x -9/4

4(6x +4)= 3(6x-9)

24x +16 = 18x-27

24x-18x = -27-16

6x/6 = -43/6


x = -7⅙

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(5)

TABULATE


Mass (kg): 31-40| 41-50| 51-60| 61-70| 71-80| 81-90


F: 3| 10| 15| 12| 6| 4


x: 35.5| 45.5| 55.5| 65.5| 75.5| 85.5


Fx: 106.5| 455| 832.5| 786| 453| 342


Class boundaries: 30.5-40.5| 40.5-50.5| 59.5-60.5| 60.5-70.5| 70.5-80.5| 80.5-90.5


(i) Mean (x-bar) = ∑fx/∑f = 2975/50 = 59.5

:. Mean = 60kg


(ii) Mode = L¹ + ( fm-fa/2fm-fa-fb) c

= 50.5. + (15-10/2*15-10-12)10

= 50.5 +(5/8)10

= 50.5+6.25

:. Mode = 56.75

Mode = 57kg(approx)

====================================


(6a)

T² = ar = 6 ...... (T¹)

T⁴ = ar³ = 54..... (T²)


Common ratio = T²/T¹

ar³/at = 54/6

r²= 9

r = ± √9 = ±3

r =3


Subtract r=3 in equation T¹

ar= 6

3a=6

a = 6/3 = 2

:. a = 2 , r =3


(i) 1st term is 2

(ii) 5th term T⁵=ar⁴

T⁵ = 2*3⁴

= 2*81

= 162


(6b)

(i)

Let pencil be x

Let pens be y

Let Ruler be z


U= 160

n(x) = 75

n(y) = 87

n(z) = 93

n(xny) =25

n(xnz) = 30

n(ynz) = 47

pd n(xnynz) = x


n(xnynz¹) = 25-x

n(xnzny¹) = 30-x

n(ynznx¹) = 47-x

n(xnynz¹) = 75-(25-x+x+30-x)

= 75 -(55-x)

= 75-55+x

= 20+x


n(ynx¹nz¹) = 87-(25-x+x+47-x)

= 87-(72-x)

= 15+x


n(znx¹ny¹) = 93-(30-x+x+47-x)

= 93-77+x

= 16+x


:. 20+x+25-x+x+30-x+15+x+47-x+16+x=160

= 153+x =160

x = 160-153

x = 7


(ii)

n(xny¹nz¹) = 20+7

= 27

:. 27 pupils has pencils only

====================================


(7a)

∆XAB = ∆ABC (corresponding angle)


:. ∆BAD + ADC + ∆ACD = 180( sum of angles at triangle)


∆CAD + 83+47= 180

∆CAD = 180-83-47

CAD = 50


:. ∆ADY = CAD ( parallel to each other)

x = 50°


(7b)

Using cosine rule

c² = a²+b²- 2abcosC

x² = 6²+8²-2(6)(8)cos120

= 36+64- 96cos120

= 36+64+48

x² = 148

x = √148

x = 12km


Using sine rule

a/sinA = b/sinB


12/sin120 = 6/sinϴ

12sinϴ = 6sin120

Sinϴ = 6sin120/12

Sinϴ = 0.4330

ϴ = sin-¹ 0.4330

ϴ = 25.66

= 26°(approx)


:. The bearing of the boat from its starting point is

360 -(26+80)

360 - 106

= 254°

====================================


(9a)

Distance PQ = ϴ/360 * 2πRcosα


Where ϴ = 11+11 = 22° and α = 12°


PQ = 22/360*2*3.142*6400*cos12°

PQ = 884*787.2*0.9781/360


PQ = 2403.9


Distance QS= ϴ/360 *2πR

Where ϴ = 44-12 = 32°


= 32/360 *2*3.142*6400

= 1286963.2/360 = 3574.9


Total distance= 2403.9+3574.9 = 5978.8

= 5980km( 3 s.f)


(9b)

Average speed = Total distance/Total time = 5978.8/8 = 747.35

= 747km/hr


(9c)

No time difference between Q and S because they are on the same longitude




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2022 NECO MATHEMATICS ANSWERS 2022 NECO EXAM Mathematics  Questions and Answers NECO Mathematics Questions and Answers 2022. NECO Maths Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2022 NECO MATHEMATICS ANSWERS. 2022 NECO EXAM Mathematics  Questions and Answers



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