# 2022 NECO MATHEMATICS ANSWERS - Verified 2022 NECO EXAM Mathematics Questions and Answers

Obj corrected use this pls

MATHS OBJ

1-10: CBBCDCCBDC

31-40: CCBABCEDDC

41-50: CCCAEDEDCE

===============================

Mathematics-THEORY

All are 101% Authentic.
Pls 2bi and 4b and 9 and 12 also corrected. We Make Sure Everything
Is 101% Correct. Sorry For The Little
Corrections. Tell Others Pls.

====================================

Type solution :

(1a)

Log¹⁰6+ Log¹⁰45 - Log¹⁰27

Log¹⁰(6*45/27) = Log(270/27)

= Log¹⁰10 = 1

(1b)

8^x = 32

2^3x = 2⁵

:. 3x = 5

x=5/3

(1c) 81⅙/27-⅑ = 3⁴*⅙/3³*-⅑ = 3⅔/3-⅓

:. 3⅔-(-⅓) = 3⅔+⅓ = 3³/³

= 3¹

= 3

====================================

(2a)

(i) Gradient (m) = y¹ - y²/x¹- x²

m = -1-0/2-3 = +1/+1=1

(ii) y - y¹= m(x-x¹)

y-0 = 1(x-3)

y = x-3

y-x+3=0

(2b)

(i) Area of ∆ABC = ½absinϴ

= ½*6*8*sin60

= 3*8*sin60

= 20.7846

= 20.78(approx)

(ii) Area of parallelogram = absinϴ

= 6*8*sin60

= 48*sin60

= 48*0.8660

= 41.6

====================================

(3a)

|PQ| = 12km, |QP| = 12km

Speed from P to Q = 6km/h

Speed from Q to P = (6+x)km/h

Total time taken 3hrs20mins

Speed = distance/time

From P to Q = 6/1*12/t

6t = 12

t = 12/6 = 2hrs

:. Time left = 3hrs 20mins - 2hrs

= 1hr 20mins

From Q to P , Speed = distance/time

6+x = 12/ 1²⁰/⁶⁰

6+x = 12/⁴/³

6+x = 12*3/4

6+x = 9

x = 9-6 = 3

(3b)

x² - (sum)x + product = 0

Sum = ⅔ + ¾= 8+9/12 = 17/12

Products = ⅔*¾ = ½

x² - 17x/12 + ½ = 0

12x² - 17x + 6 = 0

====================================

(4a)

Y = x²/ 1+x²

U=x² , V= 1+x²

du/dx = 2x , dv/dx = 2x

dy/dx = (vdu/dx - udv/dx)/v²

= (1+x²)2x - x² * 2x/(1+x²)²

= 2x+2x³-2x³/(1+x²)²

dy/dx = 2x/(1+x²)²

(4b)

⅔(3x +2) = ¾(2x -3

6x +4/3 = 6x -9/4

4(6x +4)= 3(6x-9)

24x +16 = 18x-27

24x-18x = -27-16

6x/6 = -43/6

x = -7⅙

====================================

(5)

TABULATE

Mass (kg): 31-40| 41-50| 51-60| 61-70| 71-80| 81-90

F: 3| 10| 15| 12| 6| 4

x: 35.5| 45.5| 55.5| 65.5| 75.5| 85.5

Fx: 106.5| 455| 832.5| 786| 453| 342

Class boundaries: 30.5-40.5| 40.5-50.5| 59.5-60.5| 60.5-70.5| 70.5-80.5| 80.5-90.5

(i) Mean (x-bar) = ∑fx/∑f = 2975/50 = 59.5

:. Mean = 60kg

(ii) Mode = L¹ + ( fm-fa/2fm-fa-fb) c

= 50.5. + (15-10/2*15-10-12)10

= 50.5 +(5/8)10

= 50.5+6.25

:. Mode = 56.75

Mode = 57kg(approx)

====================================

(6a)

T² = ar = 6 ...... (T¹)

T⁴ = ar³ = 54..... (T²)

Common ratio = T²/T¹

ar³/at = 54/6

r²= 9

r = ± √9 = ±3

r =3

Subtract r=3 in equation T¹

ar= 6

3a=6

a = 6/3 = 2

:. a = 2 , r =3

(i) 1st term is 2

(ii) 5th term T⁵=ar⁴

T⁵ = 2*3⁴

= 2*81

= 162

(6b)

(i)

Let pencil be x

Let pens be y

Let Ruler be z

U= 160

n(x) = 75

n(y) = 87

n(z) = 93

n(xny) =25

n(xnz) = 30

n(ynz) = 47

pd n(xnynz) = x

n(xnynz¹) = 25-x

n(xnzny¹) = 30-x

n(ynznx¹) = 47-x

n(xnynz¹) = 75-(25-x+x+30-x)

= 75 -(55-x)

= 75-55+x

= 20+x

n(ynx¹nz¹) = 87-(25-x+x+47-x)

= 87-(72-x)

= 15+x

n(znx¹ny¹) = 93-(30-x+x+47-x)

= 93-77+x

= 16+x

:. 20+x+25-x+x+30-x+15+x+47-x+16+x=160

= 153+x =160

x = 160-153

x = 7

(ii)

n(xny¹nz¹) = 20+7

= 27

:. 27 pupils has pencils only

====================================

(7a)

∆XAB = ∆ABC (corresponding angle)

:. ∆BAD + ADC + ∆ACD = 180( sum of angles at triangle)

∆CAD + 83+47= 180

:. ∆ADY = CAD ( parallel to each other)

x = 50°

(7b)

Using cosine rule

c² = a²+b²- 2abcosC

x² = 6²+8²-2(6)(8)cos120

= 36+64- 96cos120

= 36+64+48

x² = 148

x = √148

x = 12km

Using sine rule

a/sinA = b/sinB

12/sin120 = 6/sinϴ

12sinϴ = 6sin120

Sinϴ = 6sin120/12

Sinϴ = 0.4330

ϴ = sin-¹ 0.4330

ϴ = 25.66

= 26°(approx)

:. The bearing of the boat from its starting point is

360 -(26+80)

360 - 106

= 254°

====================================

(9a)

Distance PQ = ϴ/360 * 2πRcosα

Where ϴ = 11+11 = 22° and α = 12°

PQ = 22/360*2*3.142*6400*cos12°

PQ = 884*787.2*0.9781/360

PQ = 2403.9

Distance QS= ϴ/360 *2πR

Where ϴ = 44-12 = 32°

= 32/360 *2*3.142*6400

= 1286963.2/360 = 3574.9

Total distance= 2403.9+3574.9 = 5978.8

= 5980km( 3 s.f)

(9b)

Average speed = Total distance/Total time = 5978.8/8 = 747.35

= 747km/hr

(9c)

No time difference between Q and S because they are on the same longitude

==================================

Image solution

Pls Use This.
(1&2&3)

====================================

(4)

===================================

(5)

====================================

(6)

====================================

(7)

====================================

(8)

====================================

(9)

====================================

(11)

====================================

Bonus
(12)

====================================

Questions paper

NECO Mathematics Questions and Answers 2022. NECO Maths Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2022 NECO MATHEMATICS ANSWERS. 2022 NECO EXAM Mathematics Questions and Answers

## Questions Students ask about 2022 NECO EXAM Mathematics Questions and Answers

• How to get 2021 Mathematics NECO QUESTION AND ANSWERS? To get 2022 NECO MATHEMATICS ANSWERS, all you need to do is to visit gistpower.com with the pin sent to you by the admin and login. With the pin, you can have a full access to 2022 NECO MATHEMATICS ANSWERS

• When do I get Verified 2021 Mathematics NECO QUESTION AND ANSWERS? You will get 2022 NECO MATHEMATICS ANSWERS a night to the exam because Mathematics is an important subject.

• After using 2021 Mathematics NECO ANSWERS, How many am I assured of in Mathematics? You will score between 7A - 9A in Mathematics if you write verbatim 2022 NECO MATHEMATICS ANSWERS.

• How verified is your 2021 Mathematics NECO ANSWERS? Our 2022 NECO MATHEMATICS ANSWERS is 100% verified and legit and it is worthy to be trusted because it from gistpower.com which is the most trusted website for exam runs in Nigeria.

• Where do I get 2021 Mathematics NECO QUESTION AND ANSWERS? You can get 2022 NECO MATHEMATICS ANSWERS only from gistpower.com

• Is the answers on this page actually the main 2022 NECO MATHEMATICS ANSWERS? No, This is 2021 NECO MATHEMATICS ANSWERS, to get 2022 NECO MATHEMATICS ANSWERS, you need to subscribe with us.

• How do I subscribe for 2021 Mathematics NECO Questions & ANSWERS? To subscribe for 2021 Mathematics NECO Questions & ANSWERS, Message 07058713598 starting that you need 2021 Mathematics NECO Questions & ANSWERS a day to the exam.

NECO Mathematics Questions and Answers 2022. NECO Maths Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2022 NECO MATHEMATICS ANSWERS. 2022 NECO EXAM Mathematics Questions and Answers

We Need only 160 Candidates for this Year Jamb Cbt Runs. Only few slot left.

Beware of Scammers.... Please always use 07058713598 for all your transactions to avoid being scammed.
NOTE: Any answer that does not have badge can be chnaged, removed or updated anytime. The badge means that the answers have been verified 100% (if used exactly, you're to get nothing but A1) while without the badge means that the answer is still under verification. If you're not in a hurry, please wait for answer to be verified before you copy.