2024 NECO PHYSICS: NECO Physics practical Answers 2024 Exam (3209)

(1a)

Lo = 13.00cm

L | Li/cm | e= L-Lo/cm | ti/s | T =t/n/S | T²/S²

1 | 21.00 | 8.00 | 7.34 | 0.734 | 0.5388

2 | 26.20 | 13.20 | 8.86 | 0.886 | 0.7850

3 | 30.50 | 17.50 | 9.53 | 0.953 | 0.9082

4 | 35.50 | 22.50 | 10.20 | 1.020 | 1.0404

5 | 40.20 | 27.20 | 10.85 | 1.085 | 1.1772

(1axvi)

Slope, S = (∆e/cm)/(∆T²/S²) 

S = ([25.00-5.00]cm)/([1.20-0.40]/S²) = (20.00/cm)/(0.8/S²)

Slope, S = 25.00cm/S²

(1axvii)

K = 4π²S = 4×(22/7)²×25 = 4×(484/49)×25 

K = 987.76cm/S²

(1axvii)

(i) I will avoid parallax error when taking reading on the metre rule

(ii) I will check zero error of the stop watch 

(1bi)

(i) Pendulum Bob

(ii) A loaded tube suspended in a water 

(iii) The vibration of the motion of a plucked guitar string 

(1bii)

Mean time = 34.80+36+33.75/5 = 104.55/3

Mean time = 34.85s 

Mean period= 34.85/15 = 2.323seconds

=========================

(3avii)

i | R/Ω | R-¹/Ω-¹ | IA

1 | 1.00 | 1.000 | 0.32

2 | 2.00 | 0.500 | 0.32

3 | 3.00 | 0.333 | 0.28

4 | 4.00 | 0.250 | 0.26

5 | 5.00 | 0.200 | 0.24

(3aix)

Slope, S = (∆I/A)/(∆R-¹/Ω-¹) = ([0.32-0.25]/A)/([1.00-0.160]/Ω-¹)

= (0.7/A)/(0.84/Ω-¹) = 0.083AΩ

Intercept, C = 0.24A

(3ax)

K = S/C = 0.083AΩ/0.24A = 0.35Ω

(3axi)

(i) I ensured tight connections to avoid current fluctuation 

(ii) I will ensure that the key is opened when the circuit is not in used to avoid the cell being used up

(3bi)

The end of a cell is greater than it's terminal voltage because there is some potential drop across the cell due to its small internal resistance 

(3bii)

I = E/R+r 

I = 1.5/6+0.5 = 1.5/6.5

I = 0.23A

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